In the multiplication problem at the right, A and B stand for different digits. Find A and B.
B × A should have digit 4 in units place and A×A should be less than 11
as AB×A = 114
The options are
B=4 & A=1
B=2 & A=2
B=8 & A=3
From the options only feasible solution is A=3 and B=8
So in the given multiplication problem A=3 and B=8
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