If 24 gallons of water are poured into an empty tank, then 3/4 of the tank is filled. How many gallons does a full tank hold?
Let V be the full volume of tank.
3/4 of tank = 24 gallons
3/4 * V = 24
V = 24 * 4/3 = 32
The full tank will hold 32 gallons of water.
Showing posts with label Fraction. Show all posts
Showing posts with label Fraction. Show all posts
Monday
With how much money did she start?
A woman spent two-thirds of her money. She lost two-thirds of the remainder and then had $4 left. With how much money did she start?
Let M be the money the woman had with her initially.
The money she spent = \(\dfrac{2}{3}\) * M
Remaining = M - \(\dfrac{2}{3}\) * M = \(\dfrac{1}{3}\) * M
The money she lost = \(\dfrac{2}{3}\) * ( \(\dfrac{1}{3}\) * M ) = \(\dfrac{2}{9}\) * M
Remaining = \(\dfrac{1}{3}\) * M - \(\dfrac{2}{9}\) * M= \(\dfrac{1}{9}\) * M
=> \(\dfrac{1}{9}\) * M = 4
=> M = 9 * 4 = 36
She had $36 at the start.
Remaining = M - \(\dfrac{2}{3}\) * M = \(\dfrac{1}{3}\) * M
The money she lost = \(\dfrac{2}{3}\) * ( \(\dfrac{1}{3}\) * M ) = \(\dfrac{2}{9}\) * M
Remaining = \(\dfrac{1}{3}\) * M - \(\dfrac{2}{9}\) * M= \(\dfrac{1}{9}\) * M
=> \(\dfrac{1}{9}\) * M = 4
=> M = 9 * 4 = 36
She had $36 at the start.
Wednesday
Simple fraction in lowest terms
Express the extended fraction at the right as a simple fraction in lowest terms.\(\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2}}}}\)
Start working from inside.
\(\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2}}}}\) = \(\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{\dfrac{5}{2}}}}\) = \(\dfrac{1}{2+\dfrac{1}{2+\dfrac{2}{5}}}\) = \(\dfrac{1}{2+\dfrac{1}{\dfrac{12}{5}}}\) = \(\dfrac{1}{2+\dfrac{5}{12}}\) = \(\dfrac{1}{\dfrac{29}{12}}\) = \(\dfrac{12}{29}\)
Start working from inside.
\(\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{2}}}}\) = \(\dfrac{1}{2+\dfrac{1}{2+\dfrac{1}{\dfrac{5}{2}}}}\) = \(\dfrac{1}{2+\dfrac{1}{2+\dfrac{2}{5}}}\) = \(\dfrac{1}{2+\dfrac{1}{\dfrac{12}{5}}}\) = \(\dfrac{1}{2+\dfrac{5}{12}}\) = \(\dfrac{1}{\dfrac{29}{12}}\) = \(\dfrac{12}{29}\)
Sunday
Find the values of A and B in the sum of fractions
If \(\dfrac{1}{3}\) = \(\dfrac{1}{A}\) + \(\dfrac{1}{B}\) where A and B are different whole numbers.Find the values of A and B.
MetroEye: As per Fractions01
\(\dfrac{1}{3}\) = \(\dfrac{1}{3+1}\) + \(\dfrac{1}{3*(3+1)}\)
\(\dfrac{1}{3}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{12}\)
So A = 4 and B=12
MetroEye: As per Fractions01
\(\dfrac{1}{3}\) = \(\dfrac{1}{3+1}\) + \(\dfrac{1}{3*(3+1)}\)
\(\dfrac{1}{3}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{12}\)
So A = 4 and B=12
Simple fraction in lowest terms?
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