There are many numbers that divide 109 with a remainder of 4. List all two-digit numbers that have that property.
If there is a remainder of 4, then 109-4= 105 should be completely divisible by the two-digit numbers.
=> All two-digit divisors of 105.
Factors of 105 are 3,5,7.
Two digit divisors are then 3*5=15, 3*7=21, 5*7=35
The two-digit numbers that divide 109 with a remainder of 4 is 15,21 and 35.
Subscribe to:
Post Comments
(
Atom
)
hello i am a bot
ReplyDeleteThat doesn't help
DeleteThis comment has been removed by the author.
Delete