As per Progression01,
Sum of the first n terms = \(\dfrac{n}{2}\left(2a+\left(n-1\right)d\right)\)
i.e; 320 = \(\dfrac{5}{2}\left(2a+\left(5-1\right)2\right)\)
\(\dfrac{320*2}{5}\) = 2a+4*2
128=2a+8
=>a=120/2=60
The first term in the series is 60.
Wednesday
What is the smallest of five numbers?
The numbers 2,4,6 and 8 are a set of four consecutive even numbers. Suppose the sum of five consecutive even numbers is 320. What is the smallest of the five numbers?
As per Progression01,
Sum of the first n terms = \(\dfrac{n}{2}\left(2a+\left(n-1\right)d\right)\)
i.e; 320 = \(\dfrac{5}{2}\left(2a+\left(5-1\right)2\right)\)
\(\dfrac{320*2}{5}\) = 2a+4*2
128=2a+8
=>a=120/2=60
The first term in the series is 60.
As per Progression01,
Sum of the first n terms = \(\dfrac{n}{2}\left(2a+\left(n-1\right)d\right)\)
i.e; 320 = \(\dfrac{5}{2}\left(2a+\left(5-1\right)2\right)\)
\(\dfrac{320*2}{5}\) = 2a+4*2
128=2a+8
=>a=120/2=60
The first term in the series is 60.
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number facts
ReplyDeleteA number is a concept that arises from the result to have things that are an aggregate or a generalization of this concept.
you dont have to be so mean
ReplyDeleteu know there are 5th graders here right
ReplyDelete