Find the values of A and B in the sum of fractions

If  \(\dfrac{1}{3}\) = \(\dfrac{1}{A}\) + \(\dfrac{1}{B}\) where A and B are different whole numbers.Find the values of A and B.


MetroEye: As per Fractions01

\(\dfrac{1}{3}\) = \(\dfrac{1}{3+1}\) + \(\dfrac{1}{3*(3+1)}\)

\(\dfrac{1}{3}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{12}\)  

So A = 4 and B=12