Let S be the side of the square in inches.
Perimeter of Figure A = 5S+5S+1S+5S = 16S = 48 inches
One side of the square S = 48/3 = 16 inches
Perimeter of Figure B = 3S+3S+3S+4S+3S+4S = 20S = 20 *3 = 60
Perimeter of Figure B is 60 inches.
Thursday, June 11, 2015
What is the perimeter of Figure B?
The small boxes in Figures A and B at the right are congruent squares. The perimeter of Figure A is 48 inches. What is the perimeter of Figure B? (The perimeter of a figure is the distance around it.)
Let S be the side of the square in inches.
Perimeter of Figure A = 5S+5S+1S+5S = 16S = 48 inches
One side of the square S = 48/3 = 16 inches
Perimeter of Figure B = 3S+3S+3S+4S+3S+4S = 20S = 20 *3 = 60
Perimeter of Figure B is 60 inches.
Let S be the side of the square in inches.
Perimeter of Figure A = 5S+5S+1S+5S = 16S = 48 inches
One side of the square S = 48/3 = 16 inches
Perimeter of Figure B = 3S+3S+3S+4S+3S+4S = 20S = 20 *3 = 60
Perimeter of Figure B is 60 inches.
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