Let S be the side of the square in inches.
Perimeter of Figure A = 5S+5S+1S+5S = 16S = 48 inches
One side of the square S = 48/3 = 16 inches
Perimeter of Figure B = 3S+3S+3S+4S+3S+4S = 20S = 20 *3 = 60
Perimeter of Figure B is 60 inches.
Showing posts with label Congruent Squares. Show all posts
Showing posts with label Congruent Squares. Show all posts
Thursday
What is the perimeter of Figure B?
The small boxes in Figures A and B at the right are congruent squares. The perimeter of Figure A is 48 inches. What is the perimeter of Figure B? (The perimeter of a figure is the distance around it.)
Let S be the side of the square in inches.
Perimeter of Figure A = 5S+5S+1S+5S = 16S = 48 inches
One side of the square S = 48/3 = 16 inches
Perimeter of Figure B = 3S+3S+3S+4S+3S+4S = 20S = 20 *3 = 60
Perimeter of Figure B is 60 inches.
Let S be the side of the square in inches.
Perimeter of Figure A = 5S+5S+1S+5S = 16S = 48 inches
One side of the square S = 48/3 = 16 inches
Perimeter of Figure B = 3S+3S+3S+4S+3S+4S = 20S = 20 *3 = 60
Perimeter of Figure B is 60 inches.
How many different squares can be traced?
Number of 1x1 squares that can be traced = Number of squares in the figure = 21
Number of 2x2 squares that can be traced = 12
Number of 3x3 squares that can be traced = 5
Total number of squares = 21+12+5= 38
38 different squares can be traced using the lines in the figure.
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